Hydrogen Gas

Purpose: To determine the percent yield of hydrogen muff produced in the reaction of magnesium with hydrochloride vinegarish Materials: Electronic offset scale splatter measuring tube 10mL or 25mL alum cylinder Retort stand and clamp chiliad mL graduated cylinder containing about 800mL of piddle which has been brought to mode temperature bull wire 1 hole 00 rubber stopper 2.5 cm gaffe of Mg ribbon steel wool 6 mol of dm3 HCL(aq) information Table1: Quantitative observations of magnesium reacting with hydrochloride acid Substances standard including uncertainty Mass of 2.5cm magnesium 0.037g±0.0005 mode temperature19°C±0.5 heap of 6.00 dm3 HCL(aq) used15.1cm3 ±0.5 Volume of bollixoline collected ( peeing levels are equal to room pressure)36.5cm3 ±0.1 length of magnesium2.6cm±0.05 Table2: Qualitative observations of the magnesium, reacting in the hydrochloride acid SubstancesQualitative Observations 2.

5cm Magnesium (Mg) ribbon undo away thin strip hard Shiny flexile Hydrochloride acid (HCL)Transparent bonny like water The reaction occurred when the hydrochloride acid reaches the magnesium (Mg) ribbon startle to dissolve Separating the H2 gas from the water gas bubbles attached to copper wire by and by the reaction occurred (the period of 5 minutes waiting for the gas in the test tube to come to room temperature)No much air bubbles No change of colour Transparent water Gas bubbles attached to copper coil Temperature of the water subsequently the reaction19.5°C ±0.5 Pressure101.38kPa Calculations: Step 1: Equation Mg(s) + 2HCL (aq) MgCl2 (aq) + H2 (g) Step 2: pose the number of mole! s of Mg n = m/M Molar mass of Mg = 24.31g/mol m = 0.037±0.0005g n = 0.037±0.0005g ÷ 24.31g/mol n = 1.52x10-3 ±0.0005mol Uncertainty Calculations: 0.0005 ÷ 0.037g x coke = 1.4% 0.0005 ÷24.31g/mol x 100 = 0.002% 1.4% + 0.002% = 1.402% 1.402% of 0.037 = 0.0005 Therefore the uncertainty is ±0.0005 Since the...If you fate to bring forth a full essay, order it on our website: OrderEssay.net

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